Medical faculty
LESSON 5 (6 HOURS)
Themes:
1. Chemical thermodynamics. Heat effect
of dissolving reactions of salts and neutralization reactions.
2. Electrode processes. Determination of redox
potentials.
3. Measurement of pH of solutions with the help of potentiometric method.
Aim: To be able to determine heat effect of dissolving
reactions of salts and neutralization reactions; to measure redox
potentials and pH of biological liquids with the help of potentiometer; to
calculate theoretical value of redox potentials of these
systems.
PROFESSIONAL
ORIENTATION OF STUDENTS:
Bioenergetics
studies of energy transformations in the organism. The chemical energy of food
products is the main source of energy for the body. It is used in the internal
processes: breathing, blood circulation, metabolism, secretion, temperature
control. Chemical thermodynamics is the theoretical base for bioenergetics
despite lots of specific characteristics of energy metabolism in the organism. Thermochemistry renders it possible to measure energy
values of food products, which is important in nutritiology.
Electrochemical
phenomena are observed in human organism. The movements of muscles, heartbeat,
spreading of nerve impulses are accompanied by electrochemical phenomena. The
processes of biological oxidation are the primary source of energy in the body.
Knowledge of the basic concepts of reduction-oxidation processes, alterations
of reduction-oxidation potentials and direction of electron (or hydrogen atom)
transport is crucial for understanding biochemical reduction-oxidation
processes. Electrochemical analysis is widely used in medicine for
determination of pH of biological liquids.
BASIC LEVEL
1. Concept of
energy, heat effect of reaction, thermochemical
equations (secondary school course in chemistry)
2. Redox reactions. Concept of oxidantion
and reduction (secondary school course in chemistry)
3. The basics of
galvanic cells (secondary school course in physics)
4. Decimal logarithm
(secondary school course in mathematics).
STUDENTS’
SELF-PREPARATION PROGRAM.
Theme 1. Chemical thermodynamics. Heat effect of dissolving reactions of salts and neutralization
reactions.
1.
Basic concepts of chemical thermodynamics:
thermodynamic system, thermodynamic process (isobaric, isochoric, isothermal).
2.
The internal energy of system. Enthalpy. The
first law of thermodynamics.
3.
Thermochemical equations.
Standard enthalpy (heat) of formation, standard enthalpy (heat) of combustion.
4.
Hess’s law and its consequences. Calorimetry. Thermochemical
calculations.
5.
The second law of thermodynamics. Entropy.
6.
Thermodynamic criteria of spontaneous
processes.
7.
Energetic characteristics of biochemical
processes. Macroergic compounds and their importance
in the organism.
Theme 2. Electrode
processes. Determination
of redox potentials.
1.
The mechanism of electrode potential formation.
Nernst equation.
2.
The half-cells. Potential of redox systems.
3.
Standard hydrogen electrode. Standard electrode
potential.
4.
Galvanic cells. Electromotive force.
5.
Measurement of electrode potentials.
Theme 3. Measurement of pH of solutions with
the help of potentiometric method.
1.
Classification of electrodes: electrodes of the
first and second kind.
2.
Reference electrode: hydrogen electrode,
silver-silver chloride electrode, structure and their standard electrode
potential.
3.
Ion-selective (membranes) electrodes. Glass
electrode, its structure. Determination of pH.
4.
Inert oxidation-reduction electrodes, their structure
and standard electrode potential.
5.
Measurement of pH by using pH meter.
6.
Potentials in biological systems.
METHODOLOGY OF PRACTICAL CLASS (900-1200)
Theme 1. The chemical thermodynamics.
Heat effect of
dissolving reactions of salts and neutralization reactions.
Work 1. Determination of the heat effect of copper sulfate
dissolving
Materials. copper sulfate crystalline, calorimeter.
Protocol. Add 25 ml of distilled water
(mH2O) to the calorimeter internal cup, immerse
the thermometer in water and record the temperature (t1). Quickly
add 1g of CuSO4 crystalline to the cup and mix with stiller. Measure
the maximal temperature of the obtained solution (t2) with the
thermometer.
Calculate the heat
effect of salt dissolving by the formula:
Calculate the
theoretic heat effect of salts dissolving using Hess’s law, if:
CuSO4
+ 5H2O = CuSO4·5H2O DH1 = -
78.2 kJ/mol
CuSO4
+ 5H2O + aq = CuSO4·aq DH2 =
11.7 kJ/mol
DH (theoretic) = DH2 + DH1
Work 2. Determination of the heat effect of neutralization
reaction
NaOH (aq) + HCl(aq) = NaCl (aq)
+ H2O DHtheoretic = - 57.3 kJ/mol
Materials. 1mol/l HCl
solution, 1 mol/l NaOH solution, calorimeter.
Protocol. Add 30 ml of 1 mol/l HCl solution to the calorimeter internal cup,
immerse the thermometer in solution and record the temperature (t1).
Quickly add 30 ml of 1 mol/l NaOH solution to the cup,
assuming that it has the same temperature and mix with stiller. Measure the
maximal temperature of the obtained solution (t2) with the
thermometer.
Suppose,
that densities of the solutions, both of HCl and NaOH, are equal (1 g/ml). Then the mass of the solution in
the cup is the following:
Record the mcup, t1 and t2 in the
table:
Parameter |
Name |
Value |
1. mass of the internal cup |
mcup |
|
2. mass of the solution |
msolution |
|
3. heat capacity of the cup |
Ccup |
0.753 J/ g |
4. heat capacity of the solution |
Csolution |
4.184 J/ g |
5. initial temperature |
t1 |
|
6. maximal temperature |
t2 |
|
Calculate the total
heat capacity of the cup and solution:
Calculate the heat
effect of neutralization reaction by the formula:
Where:
M – molarity of solution;
V – volume of solution.
Theme 2. Electrode
processes. Determination of redox potentials
Work 3. Measurement of redox
potential of the Fe+3/Fe+2 system
Redox potential of the redox system is calculated with EMF values and measured by
the ionometer.
Materials. 0,1 mol/l Mohr's salt solution (FeSO4), 0,001
mol/l iron ammonium alum solution (Fe2(SO4)3)
Protocol. Collect galvanic
cells with a measuring electrode (the platinum electrode) and a reference
electrode (the silver-silver chloride electrode with a constant potential 0,202
±0,002 V)
Add 10 ml of 0,1 mol/l Mohr's salt solution (contain Fe2+) and 10
ml of 0,001 mol/l iron ammonium alum solution (contain Fe3+) to the
flask (or beaker). Immerse the electrodes in the solution of redox system. Measure electromotive force (EMF) of this system
by the potentiometer.
Calculate the experimental
value of the redox potential for redox
system Fe3+, Fe2+(aq) | Pt(s) by the
formula:
where: EMF value, V (measured)
eref = 0,202 V (silver-silver
chloride electrode potential)
Calculate the theoretical
value of the redox potential by the Nernst equation
for this system:
half-reaction: Fe+3(aq)
+ е- ®Fe+2(aq)
Work 4. Measurement of redox
potential of the MnO4-/Mn2+ system
Materials. 0,1 mol/l KMnO4 solution, 0,01 mol/l MnSO4
solution, H2SO4 conc.
Protocol. Collect galvanic
cells with a measuring electrode (the platinum electrode) and a reference
electrode (the silver-silver chloride electrode with a constant potential 0,202
±0,002 V)
Add 25 ml of 0,1
mol/l KMnO4 solution, 5 ml of
0,01 mol/l MnSO4 solution and 5 drops of H2SO4 conc.
(pH=1) to the flask (or beaker). Immerse the electrodes in the solution of redox system. Measure electromotive force (EMF) of this
system by the potentiometer.
Calculate the experimental
value of the redox potential for redox system MnO4-, Mn2+| Pt(s) by the
formula:
where: EMF value, V (measured)
eref = 0,202 V
(silver-silver chloride electrode potential)
Calculate the
theoretical value of the redox potential by the
Nernst equation for this system:
half-reaction: MnO4- + 8H+
+ 5e ® Mn2+ + 4H2O
Theme 3. Measurement of pH of solutions with the help of potentiometric method.
Work 5. Measurement of the pH of solutions and biological
liquids
The pH value of the solution is measured using pH electrode. It
essentially consists of a pair of electrodes: measuring (glass electrode) and
reference electrode (silver-silver chloride electrode), both dipped in the
solution of unknown pH.
Protocol. Measure pH of
solutions: acidic solution, gastric juice, urine, intestinal juice, alkaline
solution using pH meter. Record the pH value to the table, calculate the pOH values, [H3O+] and [
Example of
calculation:
pH + pOH = 14
pOH = 14 - pH
The hydronium ion concentration ([H3O+]) can be found from
pH value by the reverse mathematical operation used to determine pH.
[H3O+] = 10-pH
or [H3O+] = antilog (- pH)
pH = 5,46
5,46
= - log [H3O+]
- 5,46 = log [H3O+]
[H3O+]
= 10-5.,46 = 3,47.10-6 mol/l
(On
a calculator, calculate: press the number
-0.54, press button 10x (or two buttons INV and LOG), press button =,
get the value antilogarithm 3,47·10-6).
If you know the
value of [H3O+], find the value [
Kw= [H3O+][
Solution |
pH |
pOH |
[H3O+] |
[ |
Medium |
acid solution |
|
|
|
|
|
gastric juice |
|
|
|
|
|
urine |
|
|
|
|
|
intestinal juice |
|
|
|
|
|
alkaline solution |
|
|
|
|
|
SEMINAR DISCUSSION OF THE THEORETICAL ISSUES (1230-1400).
TEST EVALUATION AND
SITUATIONAL TASKS.
Multiple choice
tests
1. Choose standard state
of the system:
A. 101,3 kPa, 00K.
B. 101,3 kPa, 2730K.
C. 101,3 kPa, 2980K.
D. 50 kPa, 2730K.
E. 50 kPa, 2980K.
2. The concept “In
any process of an isolated system, the total energy remains the same” is:
A. The first law of
thermodynamics.
B. The second law
of thermodynamics.
C. The third law of
thermodynamics.
D. Hess’s law.
E. Kirchhoff’s law.
3. Thermodynamics
systems are classified by the number of phases into:
A. Exogenous and
endogenous.
B. Solid, liquid,
gas.
C. Homogeneous and
heterogeneous.
D. Isolated,
opened, closed
E. Reversible and
irreversible.
4. Diagram of
silver-silver chloride electrode is:
A. Pt, H2/2H+.
B. Ме/Меn+.
C. Zn/Zn2+.
D. Ag/AgCl,
KCl.
E. Hg/Hg2Cl2,
KCl.
5. Choose the formula
of Nernst equation:
A. E = E0catode
- E0anode.
B. E = E0 -
(RT/ nF) ln ([M]/ [Mn+]).
C. pH = - log [H+].
D. pH = 14- pOH.
E. E = 14 - RT/nF
Examples of tasks
solving
Task
1. The heat of formation of carbohydrates in the human body is 4.1 kcal/g.
Daily needs for carbohydrates for students are 383g. Calculate the daily needs for
carbohydrates for the student to get energy.
Answer:
∆Нform (carb)
= 4,1 kcal/g m (carb) = |
1. To solve this task, we use direct proportion: 4,1 kcal — X kcal — Answer: 1570,3 kcal |
∆Н (day) = ? |
Task
2. Calculate the heat effect of reaction of glucose oxidation, if ∆Нformation of glucose - 1272.45 kJ/mol, carbon
dioxide - 393.6 kJ/mol, water - 285.9 kJ/mol.
Answer:
∆Нform (C6H12O6)
= -1272,4 kJ/mol ∆Нform (CO2) = -393,6 kJ/mol ∆Нform (H2O) = -285,9 kJ/mol |
1. The reaction of oxidation of glucose: C6H12O6
+ 6O2 → 6CO2 + 6H2O; 2. Use the equation of the first consequences of the Hess’s law: ∆Нformation
= ∑ ∆Нf.prod
─ ∑ ∆Нf. reactant 3. Substitute these ∆Нformation
reaction products and reactants, taking into account the stoichiometric
coefficients:
|
∆Нreaction = ? |
Task 3. Can the following
reaction occur spontaneously if
Gibbs energy of SiO2(solid) =
-803,75 kJ/mol, NaOH(liquid)= -
419,5 kJ/mol, Na2SiO3(solid) = -1427,8 kJ/mol, H2O
(liquid) = -237,5 kJ/mol?
Answer:
∆G0(SiO2(solid))
= -803,75 kJ/mol ∆G0(NaOH(liquid))= - 419,5 kJ/mol, ∆G0(Na2SiO3(solid))=
-1427,8 kJ/mol, ∆G0(H2O
(liquid))= -237,5 kJ/mol |
Since ∆G<0, it is spontaneous Answer: ∆G= -22,5 kJ/mol, reaction spontaneous |
∆Greaction=? |
Task
4. The heat effect of evaporation of 1 mol of water is 40.7 kJ. How much
heat is spent a day if
Answer:
ν(H2O) = 1 mol ∆Нevaporation (H2O) = 40,7
kJ/mol m (H2O) = |
1. Find how many moles do 2. To determine heat released
according the proportion: 1 mol —
40,7 kJ 44,4 mol — X kJ X= 1807,08 kJ Answer: 1807,08 kJ |
∆Н = ? |
Task
5. Calculate the
potential at 25oC for the following cell.
Oxidation:
Cu Cu2+ + 2 e-
Eoox = 0.3370 V
Reduction: Ag+ + e- Ag
Eored = 0.7996 V
[Cu2+] = 0,024 mol/l [Ag+] = 0,048 mol/l Eoox = 0,3370 V Eored = 0,7996 V |
1. Equation for the
reaction. Cu(s) + 2
Ag+(aq) 2. Calculate the standard-state cell potential Eo = Eored - Eoox = 0,4626 V 3. Nernst equation for this
cell, note that n is 2 because two electrons are
transferred in the balanced equation for the reaction: 4. Substituting the
concentrations of Cu2+ and
Ag+ ions into this
equation gives the value for the cell potential. Answer: E = 0,373 V |
E = ? |
Task 6. Concentration of
hydrogen ions in solution is 0,001 mol/l. Calculate the pH of this solution.
Answer:
[H+] = 0,001 mol/l |
pH = -log 0,001= - log 10-3 pH = 3 Answer: pH of solution is 3 |
pH=? |
Task
7. Electrode potential of the hydrogen electrode in solution is 0,1186 V. Calculate the pH of this solution and hydrogen ion
concentration.
Answer:
E = -0,1186 V |
Nernst equation for hydrogen electrode: Therefore: E0 hydrogen electrode = 0 Answer: pH=2; [H+] = 0,01 mol/l |
pH=? [H+] = ? |
Tasks
Task
8. Calculate the heat effect of reaction if standard enthalpy
of formation for CO = -110 kJ/mol, CH4= -74,9
kJ/mol, H2O = -241,8 kJ/mol.
Task
9.
Task
10. Calculate the energetic value of
Task
11. The heat of combustion of fat in the human body is 9.3 kcal/g. Average
daily needs for fats are106 g for male students. Calculate the daily energy of
fats for male students?
Task
12. Calculate the change of Gibbs free energy of glucose oxidation under
standard conditions, if the standard Gibbs energy of glucose is 910 kJ/mol,
water - 237 kJ/mol, carbon dioxide - 394 kJ/mol. Can this
reaction occur spontaneously?
Task
13. Calculate pH of solution, in which hydrogen ion concentration is equal to 0,005 mol/l.
Task
14. Calculate hydrogen ion concentration in solution, in which potential of
hydrogen electrode is equal to 0,082 V.
Task
15. The glass electrode is placed in solution with pH=2. Calculate
electrode potential of a glass electrode.
Task
16. Calculate pH of solution, in which hydroxide ion (
Student should
know:
·
the First and Second Laws of Thermodynamics;
·
Hess’s law and its consequences;
·
concept of internal energy and enthalpy,
entropy, standard enthalpy of formation, standard enthalpy of combustion, Gibbs’
energy;
·
thermodynamic criteria of spontaneous processes
·
Nernst’s equation;
·
structure of electrodes;
·
structure of galvanic cell;
·
principle of measurement of pH with the glass
electrode;
Student should be able to:
·
determine heat effects of reaction of dissolving
of salts and neutralization reaction;
·
calculate heat effects of reactions with
standard enthalpies of formation and combustion;
·
calculate food value of products from energetic
value of proteins, fats and carbohydrates;
·
measure pH of
solutions and biological liquids;
·
calculate values of electrode potential with
the Nernst equation;
·
calculate pH, pOH, [H+], [
Multiple choice
tests
Tasks
8. -206,2 kJ/mol.
9. 47,56 kcal
10. 6459 kJ
11. 985,8 kcal
12. ∆G =
-2876, reaction spontaneos
13. pH = 2,3
14. [H+]
= 4·10-2 mol/l
15. E = -0,118 V
16. pH = 10,48
References:
1. http://intranet.tdmu.edu.ua/
Student’s facilities /Lecture presentations /Department of General Chemistry/ English
/ medical /1 course/ medical chemistry/ 06. Theoretic bases of
bioenergetics
2. http://intranet.tdmu.edu.ua/
Student’s facilities /Practical classes materials /Department of General
Chemistry/ medical chemistry/ medical/ 1 course/ English/ 05. Chemical thermodynamics
3. Atkins, Peter W.; de Paula, Julio. Physical
Chemistry (9th ed.). Oxford University Press. – 2010. – ISBN 978-0-19-954337-3.
4. Atkins, Peter W.; de Paula, Julio. Physical Chemistry
for the Life Sciences (2nd ed.). W.H. Freeman
& Company. – 2011.
5. Petrucci, Ralph H., Harwood, William S., Herring, F. G.,
and Madura Jeffrey D. General
Chemistry: Principles & Modern Applications. 9th Ed. –
6. Ebbing, D.D. General Chemistry. Fifth Edition.
– Houghton Mifflin Co.,
7. Chemistry” 3th ed. J. Mc Murry
and R. Fay; – Prentice Hall,
Methodical
instructions have been worked out by:
Associate Prof. Kyryliv M. V.
Methodical instructions were discussed and adopted at the Department
sitting
27 August 2013. Minute № 1